San Fernando

City · Peru · Ucayali

San Fernando is a city in Ucayali, Peru, with a population of about 67,844. The local time zone is America/Lima (UTC-5). The nearest major city is Pucallpa, about 3 km away.

-8.3982° S  74.5377° W
America/Lima  UTC-5
Elevation  155 m
Local time
--:--:--
Sunrise / Sunset
06:1117:50
01Map
Coordinates-8.3982, -74.5377
Coordinates (DMS)8°23′53″S, 74°32′16″W
Elevation155 m
TimezoneAmerica/Lima
02Daylight by month
12.4J
12.3F
12.1M
11.8A
11.6M
11.5J
11.6J
11.7A
12S
12.2O
12.4N
12.5D
Longest day in Dec (12.5 h), shortest in Jun (11.5 h).
03Nearby places
Pucallpa326,040 ↖  2.8 km away
Puerto Callao ↖  6 km away
San José1,939 ↖  9.5 km away
San Juan1,528 ↖  11.1 km away
San Francisco1,263 ↖  17.7 km away
Campo Verde8,945 ←  30.8 km away
Masisea ↘  34.5 km away
Nueva Requena ←  37 km away
Honoria787 ↙  45.4 km away
Tournavista903 ↓  61.8 km away
05Frequently asked questions
What time zone is San Fernando in?
San Fernando is in the America/Lima time zone (UTC-5). This offset is used for all local time in San Fernando.
Where is San Fernando located?
San Fernando is located in Ucayali, Peru. Its position is -8.3982, -74.5377.
What are the GPS coordinates of San Fernando?
The geographic coordinates of San Fernando are -8.3982, -74.5377 (8°23′53″S, 74°32′16″W). It sits at an elevation of about 155 m above sea level.
What is the population of San Fernando?
San Fernando has a population of about 67,844 people, according to GeoNames data.
← All places in Peru